In Young's double slit experiment, the wavelength of light used is 'λ'. The intensity at a point is 'I' where path difference is (\(\frac{\lambda}{4}\)). If I0 denotes the maximum intensity, then the ratio (\(\frac{I}{I_0}\)) is
1
\(\frac{1}{\sqrt{2}}\)
2
\(\frac{1}{2}\)
3
\(\frac{3}{4}\)
4
\(\frac{\sqrt3}{2}\)