Teaching HTET PGT Level 3 - 2024 Mock Test Mathematics Differential Calculus Applications of Derivatives

The minimum distance from the point (4, 2) to y2 = 8x is equal to

1
\(\sqrt 2 \)
2
\(2\sqrt 2 \)
3
2
4
\(3\sqrt 2 \)
Share: WhatsApp Telegram X

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Other Tools: chatwiz.hivanix.in mmspace.hivanix.in unogame.hivanix.in

Quick Navigation

Home

Subjects

Chapters