The equation of the circle which passes through the points (1, 0), (0, -6) and (3, 4) is

1
4x2 + 4y2 + 142x + 47y + 140 = 0
2
4x2 + 4y2 – 142x – 47y + 138 = 0
3
4x2 + 4y2 – 142x + 47y + 138 - 0
4
4x2 + 4y2 + 150x – 49y + 138 = 0

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