If \({\rm{z}} = {\rm{}} - \frac{{2\left( {1\; + \;2{\rm{i}}} \right)}}{{3\; + \;{\rm{i}}}}\) Where \(i = \sqrt { - 1}\) then the argument θ (-π < θ ≤ π) of z is
1
\(\frac{{3\pi }}{4}\)
2
\(\frac{\pi }{4}\)
3
\(\frac{{5\pi }}{6}\)
4
\(- \frac{{3\pi }}{4}\)