In quadrilateral ABCD, AC and BD are diagonals and they intersect at 60°. If AC = 3√5 cm and BD = 6√5 cm, then what is the area quadrilateral ABCD?
1
\(\frac{{45\sqrt 3 }}{2}{\rm{\;c}}{{\rm{m}}^2}\)
2
\(\frac{{43\sqrt 3 }}{2}{\rm{\;c}}{{\rm{m}}^2}\)
3
\(\frac{{63\sqrt 3 }}{2}{\rm{\;c}}{{\rm{m}}^2}\)
4
\(\frac{{35\sqrt 3 }}{2}{\rm{\;c}}{{\rm{m}}^2}\)