If \(\frac{a}{b} = \frac{3}{4}\) and \(\frac{b}{c} = \frac{{12}}{{18}}\), then \(\frac{{9{c^2} - 6{a^2}}}{{40{c^2} + 15{a^2}}}\) is equal to

1
2/11
2
2/55
3
3/45
4
6/35

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