A random variable Y obeys a normal distribution

\(P(Y)=\frac{1}{\sigma \sqrt{2 \pi}} \exp \left[-\frac{(Y-\mu)^2}{2 \sigma^2}\right]\)

The mean value of eY is

1
\(e^{\mu+\frac{\sigma^2}{2}}\)
2
\(e^{\mu-\sigma^2}\)
3
\(e^{\mu+\sigma^2}\)
4
\(e^{\mu-\frac{\sigma^2}{2}}\)

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation