Five different strains of Salmonella (1, 2, 3, 4, 5) which can utilize lactose (Lac⁺) as the sole carbon source but cannot synthesize arginine (Arg^-) are mixed with five other strains (6, 7, 8, 9, 10) that cannot utilize lactose (Lac^-) and can make arginine (Arg⁺). These strains are mixed in all possible combinations and plated on appropriate plates to get Lac⁺ Arg⁺ recombinants. The following results were obtained, where H represents 'high numbers of recombinants', L refers to 'low numbers of recombinants' and O represents 'no recombinants'.

Strain No.	1	2	3	4	5
6	H	O	O	H	L
7	H	O	O	H	L
8	O	H	H	O	O
9	O	L	L	O	O
10	O	H	H	O	O

On the basis of these results, the sex type (either Hfr, F⁺ or F^-) to each of these strains was assigned.

A. Strains 2, 3, 6, 7 are F^-

B. Strains 2, 3, 5, 6, 7, 9 are F^-

C. Strains 1, 4, 8, 10 are F⁺

D. Strains 1, 4, 8, 10 are Hfr

Which one of the following options represents a combination of all correct statements?