Let \(f(x) = e^{x^2} \) . The Taylor series expansion of f(x) about x = 0 is given by  

\(f(x) = \sum_{n=0}^\infty a_n x^n \)

Then The Coefficient of x6 will be? 

1
\(\frac{1}{3!} \)
2
\(\frac{1}{2!} \)
3
\(\frac{1}{6!} \)
4
\(\frac{1}{2 \cdot 3!} \)

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