A ball dropped from a height bounces back to half the height. If the ball is dropped from height h then after the third bounce, up until it starts falling again, it would have covered a total distance of
1
\(\frac{7}{4} h\)
2
\(\frac{21}{8} h\)
3
\(\frac{15}{8} h\)
4
\(\frac{9}{4} h\)