∆ABC ∼ ∆EDF and area (∆ABC) : area (∆EDF) = 9 :4. If AB = 5 cm, BC = 8 cm and CA = 10 cm, then DF is equal to:

1
\(5 \frac{1}{3}\) cm
2
\(3\frac{1}{4}\) cm
3
\(4\frac{2}{3}\) cm
4
\(3\frac{2}{3}\) cm

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