If the sum of the diagonals of a rhombus is L and the perimeter is 4P, find the area of the rhombus?
1
\(\frac{1}{4}\left(\mathrm{~L}^2-\mathrm{P}^2\right)\)
2
\(\frac{1}{4}\left(L^2-4 P^2\right)\)
3
\(\frac{1}{2}\left(L^2-4 P^2\right)\)
4
\(\frac{1}{4}\left(\mathrm{~L}^2+3 \mathrm{P}^2\right)\)