If the angle between the pair of tangents drawn to the circle x2 + y2 - 2x + 4y + 3 = 0 frorm (6, -5) is θ, then tanθ =

1
\(\frac{5}{8}\)
2
\(\frac{15}{8}\)
3
\(\frac{8}{15}\)
4
\(\frac{19}{8}\)

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