The capacitance of a capacitor becomes 7/6 times its original value if a dielectric slab of thickness t = \(\frac{2}{3}\)d is introduced in between the plates: where d is the separation between the plates. The dielectric constant of the slab is:
1
\(\frac{11}{7}\)
2
\(\frac{7}{11}\)
3
\(\frac{11}{14}\)
4
\(\frac{14}{11}\)