Let α ∈ (0, α) and \(A = \begin{bmatrix} 1 & 2 & \alpha \\\ 1 & 0 & 1 \\\ 0 & 1 & 2 \end{bmatrix}\).
If det(adj(2A - AT). adj(A - 2AT)) = 28, then (det(A))2 is equal to:
1
1
2
49
3
16
4
36
Let α ∈ (0, α) and \(A = \begin{bmatrix} 1 & 2 & \alpha \\\ 1 & 0 & 1 \\\ 0 & 1 & 2 \end{bmatrix}\).
If det(adj(2A - AT). adj(A - 2AT)) = 28, then (det(A))2 is equal to: