Teaching DSSSB TGT Mock Test 2025 Mathematics Differential Equations Solution of Differential Equations
The solution of the given initial value problem \(\frac{{dy}}{{dx}} = {e^{2x + y}},y(0) = 0\) is
1
\(y = \log \left( {\frac{2}{{3 - {e^{2x}}}}} \right)\)
2
\(y = \log \left( {\frac{{3 - {e^{2x}}}}{2}} \right)\)
3
\(y = \left( {\frac{2}{{3 - {e^{2x}}}}} \right)\)
4
\(y = \left( {\frac{{3 - {e^{2x}}}}{2}} \right)\)