Teaching DSSSB TGT Mock Test 2025 Engineering Mathematics Differential Equations Higher Order Linear Differential Equations with Constant Coefficients
The solution of differential equation
(D3 + D2 + 4D + 4) y = 0 is
1
Y = A cos 2x + B sin 2x
2
Y = Ae - x + B cos 2x + C sin 2x
3
Y = Aex + B cos 2x + C sin 2x
4
Y = Ae - 2x + B cos 2x + C sin x