Teaching DSSSB TGT Mock Test 2025 Engineering Mathematics Differential Equations Partial Differential Equations
The solution of the partial differential equation \(2\frac{{{\partial ^2}z}}{{\partial {x^2}}} + 5\frac{{{\partial ^2}z}}{{\partial x\;\partial y}} + 2\frac{{{\partial ^2}z}}{{\partial {y^2}}} = 0\) will be
1
z = f(y + 2x) + ϕ(2y – x), where f and ϕ are arbitrary functions
2
z = f(y + 2x) + ϕ(2y + x), where f and ϕ are arbitrary functions
3
z = f(y – 2x) + ϕ(2y + x), where f and ϕ are arbitrary functions
4
z = f(y – 2x) + ϕ(2y – x), where f and ϕ are arbitrary functions