Using Green’s theorem, the value of the integral \(\mathop \smallint \limits_C \left( {xy\;dy - {y^2}\;dx} \right)\), where C is the square, cut from the first quadrant by the lines x = 1 and y = 1, will be.
1
1
2
\(\frac{1}{2}\)
3
\(\frac{5}{3}\)
4
\(\frac{3}{2}\)