The solution of the differential equation \(\rm\frac{dy}{dx}+\frac{2xy}{1+x^2}=\frac{1}{\left(1+x^2\right)^2}\) is :

1
y(1 + x2) = c + tan–1x
2
\(\rm\frac{y}{1+x^2}\) = c + tan−1x
3
y log (1 + x2) = c + tan–1x
4
y (1 + x2) = c + sin–1x

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