If y = y(x) is the solution of the differential equation \(\rm \frac{dy}{dx}+2y=\sin (2x), y(0)=\frac{3}{4}\), then \(\rm y\left(\frac{\pi}{8}\right)\) is equal to 

1
\(\rm e^{-\pi/8}\)
2
\(\rm e^{-\pi/4}\)
3
\(\rm e^{\pi/4}\)
4
\(\rm e^{\pi/8}\)

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