If z2 + z + 1 = 0, where z is a complex number, then \(\left(z+\frac{1}{z}\right)^2+\left(z^2+\frac{1}{z^2}\right)^2+\cdots+\left(z^6+\frac{1}{z^6}\right)^2\)

1
12
2
10
3
14
4
8

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