Teaching DSSSB TGT Mock Test 2025 Mathematics Differential Equations Solution of Differential Equations
The solution of the equation (2y − 1) dx − (2x + 3) dy = 0 is :
1
\(\rm\frac{2x−1}{2y+3}\) = k
2
\(\rm\frac{2y+1}{2x−3}\) = k
3
\(\rm\frac{2x+3}{2y−1}\) = k
4
\(\rm\frac{2x−1}{2y−1}\) = k