The sine of the angle between the straight line \(\rm \frac{x-2}{3}=\frac{y-3}{4}=\frac{z-4}{5}\) and the plane 2x − 2y + z = 5 is

1
\(\frac{10}{6 \sqrt{5}}\)
2
\(\frac{4}{5 \sqrt{2}}\)
3
\(\frac{2 \sqrt{3}}{5}\)
4
\(\frac{\sqrt{2}}{10}\)

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