If A = \( \left[\begin{array}{lll}0 & 1 & 0 \\ 2 & 0 & 2 \\ 0 & 3 & 0 \\ 4 & 0 & 4\end{array}\right]\), B = \( \left[\begin{array}{cc}5 & 6 \\ −3 & 2 \\ −1 & 0\end{array}\right]\), C = \( \left[\begin{array}{ccccc}1 & 3 & 5 & 2 & −1 \\ 2 & 4 & −5 & −4 & −2\end{array}\right]\) and D = (AB)C, then d34 in the matrix D is

1
0
2
12
3
−42
4
1

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