In a ΔABC, DE ∥ BC, where D is a point on AB and E is a point on AC. If DE divides the area of ΔABC into two equal parts, then DB ∶ AB is equal to :
1
\(\sqrt2\) ∶ \(\sqrt3\)
2
\(\sqrt2\) ∶ \(\sqrt2\) + 1
3
\(√2\) + 1 ∶ \(\sqrt2\)
4
\(\sqrt2\) - 1 ∶ \(\sqrt2\)