If the circles x2 + y2 + 2x + 2ky + 6 = 0, x2 + y2 + 2ky + k = 0 intersect orthogonally, then k is 

1
2 or \(-\frac{3}{2}\)
2
-2 or \(-\frac{3}{2}\)
3
2 or \(\frac{3}{2}\)
4
-2 or \(\frac{3}{2}\)

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