If \(\frac{(1 + i)x - 2i}{3 + i}+\frac{(2-3i)y+i}{3 - i}= i\) then the real values of x and y are given by
1
x = -3, y = -1
2
x = 3, y = - 1
3
x = 3, y = 1
4
x = 1, y = -3
If \(\frac{(1 + i)x - 2i}{3 + i}+\frac{(2-3i)y+i}{3 - i}= i\) then the real values of x and y are given by