If x = 3 tan t and y = 3 sec t, then the value of \(\frac{{{d^2}y}}{{d{x^2}}}\) at \(t = \frac{\pi }{4}\), is

1
\(\frac{3}{{2\sqrt 2 }}\)
2
\(\frac{1}{{3\sqrt 2 }}\)
3
\(\frac{1}{6}\)
4
\(\frac{1}{{6\sqrt 2 }}\)

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