If \(\rm\displaystyle\int\frac{3 e^x–5 e^{–x}}{4 e^x+5 e^{–x}}\) dx = ax + b log |4ex + 5e–x| + C, then
1
a = \(\frac{–1}{8}\), b = \(\frac{7}{8}\)
2
a = \(\frac{1}{8}\), b = \(\frac{7}{8}\)
3
a = \(\frac{–1}{8}\), b = \(\frac{–7}{8}\)
4
a = \(\frac{1}{8}\), b = \(\frac{–7}{8}\)