Let f ∶ R − \(\left\{\frac{3}{5}\right\}\)R be defined by f(x) = \(\rm \frac{3 x+2}{5 x−3}\). Then

1
f–1(x) = f (x)
2
f–1(x) = –f(x)
3
(f o f)x = –x
4
f−1(x) = \(\frac{1}{19}\) f(x)

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