A stone is thrown vertically with the velocity which would just carry it to height of 100 feet. Two seconds later another stone is projected vertically from the same place with the same velocity, find when and where will they meet?
1
\(3\frac{1}{2}\) seconds, 476 feet
2
\(3\frac{1}{3}\) seconds, 476 feet
3
\(3\frac{1}{2}\) seconds, 84 feet
4
\(3\frac{1}{3}\) seconds, 84 feet