Two dices are thrown and the turned up numbers are added. If one knows that the numbers turned up are different, what is the probability that the sum is 12?
1
0
2
1
3
\(\frac{1}{6}\)
4
\(\frac{1}{12}\)
Two dices are thrown and the turned up numbers are added. If one knows that the numbers turned up are different, what is the probability that the sum is 12?