Teaching UP TGT Mock Test Series 2025 Mathematics Integral Calculus Definite Integrals

\(\rm \displaystyle\int_0^1\dfrac{tan^{-1}x}{(1 + x^2)}dx\) is equal to

1
1
2
\(\dfrac{\pi^2}{8}\)
3
\(\dfrac{\pi^2}{32}\)
4
\(\dfrac{\pi^2}{3}\)
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