\(\int {\frac{{\cos x - 1}}{{\cos x + 1}}} dx = \)

1
2 tan \(\frac{x}{2}\) - x +c
2
\(\frac{1}{2}\) tan \(\frac{x}{2}\) - x + c
3
​x - \(\frac{1}{2}\) tan \(\frac{x}{2}\) + c 
4
x - 2 tan \(\frac{x}{2}\) + c

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