Teaching MPPSC Assistant Professor Mock Test Series 2025 Engineering Mathematics Calculus Multiple Integrals
Let \(I = \mathop \smallint \nolimits_{x = 0}^1 \mathop \smallint \nolimits_{y = 0}^{{x^2}} x{y^2}dydx.\) Then, I may also be expressed as
1
\(\mathop \smallint \nolimits_{y = 0}^1 \mathop \smallint \nolimits_{x = 0}^{\sqrt y } x{y^2}dxdy\)
2
\(\mathop \smallint \nolimits_{y = 0}^1 \mathop \smallint \nolimits_{x = \sqrt y }^1 y{x^2}dxdy\)
3
\(\mathop \smallint \nolimits_{y = 0}^1 \mathop \smallint \nolimits_{x = \sqrt y }^1 x{y^2}dxdy\)
4
\(\mathop \smallint \nolimits_{y = 0}^1 \mathop \smallint \nolimits_{x = 0}^{\sqrt y } y{x^2}dxdy\)