The average energy U of a 1-D quantum oscillator of frequency \(\omega \) and in contact with a heat bath at temperature T is given by:

1
\(U = \frac{1}{2} \hbar \omega \coth(\frac{\beta \hbar \omega}{2}) \)
2
\(U = \frac{1}{2} \hbar \omega \cosh(\frac{\beta \hbar \omega}{2}) \)
3
\(U = \frac{1}{2} \hbar \omega \sinh(\frac{\beta \hbar \omega}{2}) \)
4
\(U = \frac{1}{2} \hbar \omega \tanh(\frac{\beta \hbar \omega}{2}) \)

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation