if y1/m + y-1/m = 2x, then

1
(x2 - 1) yn+2 – (2n + 1) x yn+1 + (-n2 + m2)yn = 0
2
(x2 - 1) yn+2 + (2n + 1) x yn+1 + (n2 - m2)yn = 0
3
(x2 - 1) yn+2 – (2n + 1) x yn+1 + (-n2 - m2)yn = 0
4
(x2 - 1) yn + 2 + (2n + 1) x yn+1 + (m2 + n2)yn = 0

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