In the given nuclear reaction, the element X is:
\({ }_{11}^{22} \mathrm{Na}\) → X + e+ + v
1
\({ }_{12}^{22} \mathrm{Mg}\)
2
\({ }_{11}^{23} \mathrm{Na}\)
3
\({ }_{10}^{23} \mathrm{Na}\)
4
\({ }_{10}^{22} \mathrm{Ne}\)
In the given nuclear reaction, the element X is:
\({ }_{11}^{22} \mathrm{Na}\) → X + e+ + v