If x2 - 5x - 14 > 0 ⟹ x lie outside [α , β], then \(\frac{\alpha}{\beta}\) =

1
\(\frac{-2}{7}\)
2
\(\frac{-7}{2}\)
3
\(\frac{2}{7}\)
4
More than one of the above
5
None of the above

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