Magnetic field due to the current carrying wire as shown in the figure at point "O" will be:

1
\(\frac{\mu_0 I}{2R}\)
2
\(\frac{\mu_0 I}{4R}\)
3
\(\frac{\mu_0 I}{2\pi R}\)
4
\(\frac{\mu_0 I}{4\pi R}\)

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