If  \(f'(x) \ =\ sin^{-1}[2(\frac{2tanx\ -\ 2tan^3x}{sec^4x})]\)\(\frac{-\pi}{2}\ <\ x\ <\ \frac{\pi}{2}\) and f(1) = 2, then the value of f(2) will be 

1
-8
2
4
3
8
4
-4

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation