A box contains 20 electric bulbs, out of which 4 are defective. Two bulbs are chosen at random from this box. The probability that at least one of these is defective is :
1
\(\frac{12 }{19 }\)
2
\(\frac{7}{19 }\)
3
\(\frac{91}{95 }\)
4
\(\frac{4}{19 }\)