If 18\(\frac{2}{11}\)% of a = 45\(\frac{5}{11}\)% of b, then find the value of \(\frac{2a+6b}{17a}\).

1
\( \frac{22}{85}\)
2
\( \frac{17}{85}\)
3
\( \frac{32}{85}\)
4
None of the above

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