A square and an equilateral triangle have equal perimeters. If the diagonal of the square is \(12\sqrt{2} \) cm, then the area of the triangle is:

1
\(64\sqrt{5} \) cm2
2
\(67\sqrt{2} \) cm2
3
\(64\sqrt{3} \) cm2
4
\(65\sqrt{3} \) cm2

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