Teaching Bihar STET Paper 1 (माध्यमिक) Mock Test 2024 Quantitative Aptitude Geometry Triangles, Congruence and Similarity
It is given that Δ ABC ~ Δ PQR, with \(\rm \frac{BC } { QR }=\rm \frac{1 } {3 }\). Then, \(\rm \frac{ar(PRQ) } {ar(BCA) }\) is equal to
1
9
2
3
3
\(\rm \frac{1 } { 3 }\)
4
\( \frac{1 } { 9 }\)