If tan θ = \(a\over b\), then \(a \ sin \ θ\ –\ b\ cos \ θ \over a \ sin \ θ \ + \ b \ cos \ θ\) equals

1
\(a^2\over a^2 + b^2\)
2
\(b^2\over a^2 + b^2\)
3
\(a^2 + b^2\over a^2 - b^2\)
4
\(a^2 - b^2\over a^2 + b^2\)

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