If x + y = 1 and x2 + y2 = 41, then what is the value of \(\frac{1}{x} + \frac{1}{y}\)?

1
\(\frac{1}{10}\)
2
\(\frac{1}{10}\)
3
-\(\frac{1}{20}\)
4
\(\frac{1}{20}\)

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