SSC SSC CHSL (Tier I & Tier II) Mock Test Series 2025 (New) Quantitative Aptitude Geometry Triangles
D is a point on side AC of a triangle ABC such that AD = BD, CD = BC and \(\angle BAC\) = 30°. Then, \(\angle ABC\)+ \(\angle BDC\) is equal to :
1
\(120^{\circ}\)
2
\(130^{\circ}\)
3
\(135^{\circ}\)
4
\(150^{\circ}\)