If \(x=t+\frac{1}{t}, y = t - \frac{1}{t}\) then \(\frac{d^2y}{dx^2}\) equal to:

1
-4t3(t2 - 1)-3
2
 \(\frac{4t^3}{(t^2-1)^3}\)
3
(t2 + 1)(t2 - 1)-1
4
-4t2(t2 - 1)-2

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